factorize: 4(x-2)^2+12(x-2)
^2(系2次方)
唔好淨系比答案,其實唔比都得
*我主要系想知點做(step)
最好比埋點解(唔比都得既...我自己了解is ok)
列晒D Step
有條數想問 快~~~
2012-10-28 4:29 am
回答 (5)
2012-10-28 3:11 pm
✔ 最佳答案
Using 'common factor' method to factorize 4(x-2)^2 + 12(x-2)2012-10-28 07:14:17 補充：
As these two terms has common factor 4(x-2), so
4(x-2)^2 + 12(x-2)
= 4(x-2)[(x-2) + 3]
= 4(x-2)(x-2+3)
= 4(x-2)(x+1)
2012-10-28 11:45 pm
4(x-2)^2+12(x-2)
=4(x-2)[(x-2)+3]
=4(x-2)(x+1)
當4(x-2)^2+12(x-2)=0時
4(x-2)(x+1)=0
x=2 或x=-1
=4(x-2)[(x-2)+3]
=4(x-2)(x+1)
當4(x-2)^2+12(x-2)=0時
4(x-2)(x+1)=0
x=2 或x=-1
2012-10-28 6:10 am
4(x-2)^2+12(x-2)
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
=4(x^2-x-2)
=4(x+1)(x-2)
去到4x^2-4x-8這步可以用計算機計算的，用formula1（fx-50FH）
a是4，b是-4，c是-8
就可以出答案了。
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
=4(x^2-x-2)
=4(x+1)(x-2)
去到4x^2-4x-8這步可以用計算機計算的，用formula1（fx-50FH）
a是4，b是-4，c是-8
就可以出答案了。
參考: me
2012-10-28 5:15 am
4(x-2)^2+12(x-2)
=4[x^2-(2*2*x)+4]+12x-24
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
=(2x-4)(2x+2)
→x=2或-1
=4[x^2-(2*2*x)+4]+12x-24
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
=(2x-4)(2x+2)
→x=2或-1
2012-10-28 5:05 am
4(x-2)^2+12(x-2)
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
x=2 or x=-1
2012-10-27 21:09:21 補充：
你本書應該都有提到(a-b)^2
=a^2-2ab+b^2
(記住背)
仲有4x^2-4x-8果到禁cal機programme1入data就可以搵到x=咩
=4(x^2-4x+4)+12x-24
=4x^2-16x+16+12x-24
=4x^2-4x-8
x=2 or x=-1
2012-10-27 21:09:21 補充：
你本書應該都有提到(a-b)^2
=a^2-2ab+b^2
(記住背)
仲有4x^2-4x-8果到禁cal機programme1入data就可以搵到x=咩
收錄日期: 2021-04-16 15:07:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121027000051KK00562