polarity vs molecular size

2012-10-28 12:48 am
Considering the boiling point of 1-iodohexane is 18x degree and that of 1-chlorohexane is 13x degree.

I want to know why the b.p. of 1-chlorohexane is lower as the polarity of chlorine is higher that means it is more polar than 1-iodohexane. Therefore, the van der Waal's force of 1- chlorohexane should be stronger and hence b.p. of it should be higher.

In my chem textbook, it states that "For molecules of comparable molecular sizes and shapes, van der Waal' forces depend ""largely"" on the polarity of molecules".

Also, for the polar molecules like 1-iodohexane, the molecules have already had permanent diople-permanent diople. Would dispersion force also exist?

*I am in dse level.

回答 (1)

2012-11-02 10:43 pm
✔ 最佳答案
You have to consider the size of the molecule . The much large iodine atoms in iodohexane form stronger van der Waal bonds to the adjacent molecules than the chlorohexane . Since iodine has more electrons in its orbits to generate higher intermolecular force , it takes more energy to separate their molecules hence higher B P .


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