Small blocks, each with mass m , are clamped at the ends and at the center of a
rod of length L and negligible mass.
1. Compute the moment of inertia of the system about an axis perpendicular to
the rod and passing through the center of the rod.
Express your answer in terms of the given quantities.
2. Compute the moment of inertia of the system about an axis perpendicular to the rod and passing through a point one-fourth of the length from one end.
Express your answer in terms of the given quantities.
Small blocks
2012-10-26 9:47 pm
回答 (1)
2012-10-29 11:42 pm
✔ 最佳答案
Moment of inertia = 2 x [ m.(L/2)^2] = (mL^2)/2----------------------------------------
Moment of inertia = m(L/4)^2 + m(L/4)^2 + m(3L/4)^2 = (11/16)mL^2
收錄日期: 2021-04-29 17:49:35
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