MQ50 --- Limit
回答 (3)
2012-10-26 5:24 am
✔ 最佳答案
Consider y = x^x, ln y = x lnxlim (x -> 0) ln y
= lim (x -> 0) x lnx
= lim (x -> 0) lnx/(1/x)
= lim (x -> 0) (1/x)/(-1/x^2) (L'Hôpital's rule)
= lim (x->0) -x
= 0
So, lim (x->0) x^x = lim (x->0) exp(ln y) = 1
2012-10-26 8:13 pm
Thanks for the link.
2012-10-26 6:20 am
收錄日期: 2021-04-13 19:05:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121025000051KK00360