From a pack of 52 cards, a hand of 5 cards is dealt.
How many of these hands contain one red and four black cards?
Combinations (Maths C)...................?
2012-10-23 8:51 am
回答 (1)
2012-10-23 8:59 am
✔ 最佳答案
We assume that the cards dealt are NOT replaced.=> P(R,B,B,B,B) = (26/52)(26/51)(25/50)(24/49)(23/48)
Now, the order of the 5 cards is unimportant, so we have 52C5 ways this can happen.
=> 52C5 x (26/52)(26/51)(25/50)(24/49)(23/48) = 77,740 ways
:)>
收錄日期: 2021-04-21 01:28:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121023005129AAh9o4z