有條三角學ge方程唔識解，唔該曬啦！！

4sinxcosx =3tan2x-6tan2x sin²x
2sin2x =3tan2x-6tan2x sin²x
2sin2x =3tan2x(1-2sin²x)
2sin2x =3tan2x cos2x
2sin2x /cos2x =3tan2x
2tan2x =3 tan2x

x = 0, π or 2π (Answer)

When x = 0
4sin(0)cos(0) =3tan2(0)-6tan2(0) sin²(0)
4(0)( π/4) = 3(0)-6(0) (0)
0 = 0

When x = π
4sin(π)cos(π) =3tan(2π)-6tan(2π) sin²( π)
4(0)( -1) = 3(0)-6(0) (0)
0 = 0

When x = 2π
4sin(2π)cos(2π) =3tan(4π)-6tan(4π) sin²(2π)
4(0)(1) = 3(0) -6(0)(0)
0 = 0