數學(未知數)急,20點>.<

方程:
1)26x-x=125
25x=125
x=5
2)3c-4(c+2)=0
3c-4c-8 = 0
-1c = 8
c = -8

3)2x+5x=140
7x=140
x=20

簡化:
1)2x+6b-2x+4
=6b+4
=2(3b+2)

2)2(3x-4)-6+x
=6x-8-6+x
=7x-14
=7(1-2)

3)12p-(x/4)-3p
= 9p-(x/4)

4)2x+3j-2a+5+3g-8
= 2x+3j-2a-3+3g
= 2(x-a) + 3(j-1+g)

5)2(3a+6)+2f-6+8+9-15
= 2(3a+6+f) -4

方程:
1)26x-x=125
25x=125
x=5
2)3c-4(c+2)=0
3c-4c-2=0
-c=2
c-2

3)2x+5x=140
7x=140
x=20
簡化:
1)2x+6b-2x+4
=6b+4
=2(3b+2)
2)2(3x-4)-6+x
=6x-8-6+x
=7x-14
=7(x-2)
3)12p-(x/4)-3p
=9p-(x/4)
4)2x+3j-2a+5+3g-8
=2x-2a+3j+3g-3
=2(x-a)+3(j+g-1)
5)2(3a+6)+2f-6+8+9-15
=6a+12+2f+8
=2(3a+6+f+4)

2012-10-23 09:50:27 補充：
5)2(3a+6)+2f-6+8+9-15
=6a+12+2f-4
=2(3a+6+f-2)
sorry,我看錯了

2012-10-23 09:51:11 補充：
2)3c-4(c+2)=0
3c-4c-2=0
-c=2
c=-2

2012-10-23 09:52:22 補充：
2)3c-4(c+2)=0
3c-4c-8=0
-c=8
c=-8
sorry,我看錯了

1)
26x-x=125
25x=125
x=5

2)
3c-4(c+2)=0
3c-4c-8=0
-x=8
x=-8

3)
2x+5x=140
7x=140
x=20

1)
2x+6b-2x+4
=6b+4

2)
2(3x-4)-6+x
=6x-8-6+x
=7x-14

3)
12p-(x/4)-3p
=9p-(x/4)

4)
2x+3j-2a+5+3g-8
=2x-2a+3j+3g-3
=2(x-a)+3(j+q-1)

5)
2(3a+6)+2f-6+8+9-15
=6a+12+2f-4
=6a+2f+8

方程:
1)26x-x=125
25x=125
x=125/25
x=5

2)3c-4(c+2)=0
3c-4c-8=0
-1c-8=0
c=-8

3)2x+5x=140
7x=140
x=140/7
x=20

簡化:
1)2x+6b-2x+4
=6b+4
=2(3b+2)

2)2(3x-4)-6+x
=6x-8-6+x
=7x-14
=7(x-2)

3)12p-(x/4)-3p
=9p-(x/4)

4)2x+3j-2a+5+3g-8
=2x-2a+3j+3g+5-8
=2(x-a)+3(j+g)-3
=2(x-a)+3(j+g-1)

5)2(3a+6)+2f-6+8+9-15
=6a+12+2f-6+8+9-15
=6a+2f+8
=2(3a+f+4)

1)26x-x=125
25x=125
x=5

2)3c-4(c+2)=0
3c-4c-8=0
-c-8=0
c=-8

3)2x+5x=140
7x=140
x=20

1)2x+6b-2x+4
=6b+4
=2(3b+2)

2)2(3x-4)-6+x
=6x-8-6+x
=7x-14
=7(x-2)

3)12p-(x/4)-3p
=9p-(x/4)

4)2x+3j-2a+5+3g-8
=2x+3j-2a+3g-3
=2(x-a)+3(j+g-1)

5)2(3a+6)+2f-6+8+9-15
=6a+12+2f-4
=6a+2f+8
=2(3a+f+4)