Solve the following equations where p and q are real constants. Express the answers in terms of p and q.
1.(x^2)-(p+q)x+(p+1)(q-1)=0
THX
F.3 log/fact/quad eq
2012-10-23 4:18 am
回答 (2)
2012-10-23 4:48 am
✔ 最佳答案
x² - (p + q)x + (p + 1)(q - 1) = 0x² - (p+ 1)x – (q – 1)x + (p + 1)(q – 1) = 0x(x – p – 1) – (q – 1)(x – p – 1) = 0(x – p – 1)(x – q + 1) = 0x – p – 1 = 0 or x – q + 1 = 0x = p + 1 or x = q – 1 I HOPE THIS CAN HELPYOU! ~ ^_^2012-10-22 21:39:16 補充：
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參考: My Maths World
2012-10-23 4:47 am
x^2 - (p+q)x + (p+1)(q-1) = 0
2012-10-22 20:50:10 補充：
==> [x - (p+1)][x - (q-1)] = 0
==> x - (p+1) =0 OR x - (q-1) = 0
==> x = p+1 OR x = q-1
2012-10-22 20:50:10 補充：
==> [x - (p+1)][x - (q-1)] = 0
==> x - (p+1) =0 OR x - (q-1) = 0
==> x = p+1 OR x = q-1
收錄日期: 2021-04-13 19:04:00
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