8q2次方+2r+4q-2r2次方
Factorize the following 求步驟 唔該!
8q2次方+2r+4q-2r2次方
2012-10-22 3:36 am
回答 (5)
2012-10-23 4:53 am
✔ 最佳答案
= 8q² + 2r + 4q - 2r²= 2(4q² - r² + 2q + r)= 2[(2q – r)(2q + r) + (2q + r)]= 2(2q + r)(2q – r + 1) I HOPE THIS CAN HELP YOU! ~ ^_^
參考: My Maths World
2012-10-23 3:27 am
8q^2+2r+4q-2r^2
=8q^2+4q+2r-2r^2
=4q(2q+1)+2r(1-r)
=8q^2+4q+2r-2r^2
=4q(2q+1)+2r(1-r)
2012-10-22 4:01 am
8q2次方+2r+4q-2r2次方
=8q^2+2r+4q-2r^2
=4q(2q+1)+2r(1-r)
=8q^2+2r+4q-2r^2
=4q(2q+1)+2r(1-r)
2012-10-22 3:51 am
8q2次方+2r+4q-2r2次方
=8q2次方+4q+2r-2r2次方
=4q(2q+1)+2r(1-r)
=8q2次方+4q+2r-2r2次方
=4q(2q+1)+2r(1-r)
2012-10-22 3:44 am
唔該你分清邊個係數字邊個係次方
收錄日期: 2021-04-13 19:04:49
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