A tank of liquid is heated by a heater. the heater delievers 2.7 MJ of energy in 30 min.
Q: assume 80% of the energy is delievered to the liquid.How long will it take to transfer 1 MJ of energy to the liquid? 我計到533s 但ANS係833s.....
f.3 physics題 10分!!
2012-10-22 12:20 am
回答 (2)
2012-10-26 12:56 am
✔ 最佳答案
First, we need to find out how much time is needed to transfer 1 J of energy to the liquid.(30*60s)/ (2.7*1000000J*80%)
=1/1200 S/J
Since we need to transfer 1MJ of energy to the liquid, we can just simply multiply the result calculated by 1 MJ.
The time needed
=1/1200 * 1*1000000 s
=833.333...s
=833s(corr. to 3 sig fig)
參考: The love to physics
2012-10-22 12:53 am
[30(min)/(2.7(MJ)*80%)]*60(MIN)
=(30/2.16)*60
=13.888888...*60
=833.3333333...
=833s(corr. to the nearest 1 s)
=(30/2.16)*60
=13.888888...*60
=833.3333333...
=833s(corr. to the nearest 1 s)
收錄日期: 2021-04-16 15:14:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121021000051KK00342