why
{k(x+2)-2k+2}/(x+2)
=k+{(2-2k)/+2)}
maths
2012-10-21 10:46 pm
回答 (3)
2012-10-21 11:22 pm
✔ 最佳答案
=k(x+2)/(x+2) + (-2k+2)/(x+2)=k+{(2-2k)/(x+2)}
2012-10-22 4:22 am
{k(x+2)-2k+2}/(x+2)
={k(x+2)}/(x+2)+(-2k+2)/(x+2)
=k+{(-2k+2)/(x+2)}
=k+{(2-2k/x+2)}
={k(x+2)}/(x+2)+(-2k+2)/(x+2)
=k+{(-2k+2)/(x+2)}
=k+{(2-2k/x+2)}
2012-10-21 11:35 pm
ask your teacher
收錄日期: 2021-04-22 00:55:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121021000051KK00271