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2012-10-19 5:17 am
cos²x-cos²y=sin²(x-y)-2sinxcosysin(x-y)

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回答 (2)

2012-10-19 9:46 pm
✔ 最佳答案
cos²x - cos²y

= ( cosx - cosy ) ( cosx + cosy )

= ( - 2 sin(x + y)/2 sin(x - y)/2 ) ( 2 cos(x + y)/2 cos(x - y)/2 )

= - 2 sin(x + y)/2 cos(x + y)/2 * 2 sin(x - y)/2 cos(x - y)/2

= - sin(x + y) sin(x - y)

= ( - sinx cosy - cosx siny ) sin(x - y)

= ( sinx cosy - cosx siny - 2 sinx cosy ) sin(x - y)

= ( sin(x - y) - 2 sinx cosy ) sin(x - y)

= sin²(x - y) - 2 sinx cosy sin(x - y)
2012-10-20 4:19 am
I'd prefer to start from RHS.


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