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急! F4 Basic Trigonometry ex22
2012-10-18 1:38 am
回答 (1)
2012-10-18 3:37 am
✔ 最佳答案
6. max=-1, min=-37a. 2(sinx)^2 = 3cosx
2(1-(cosx)^2)=3cosx
2-2(cosx)^2=3cosx
0 = 2(cosx)^2 + 3cosx -2
7b. (2cosx-1)(cosx+2)=0
cosx=1/2 or cosx=-2(rejected)
x=60, 300 degree
8a. 1-(sinx)^2 / cosx
=(cosx)^2 / cosx
= cosx
8b. max=0, min=-1
收錄日期: 2021-04-13 19:04:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121017000051KK00318