f.5 m2 maths~

2012-10-17 7:12 am
lim [ sinx / (π -x) ]
x→π

evaluate the following limit

回答 (1)

2012-10-17 7:29 am
✔ 最佳答案
Set y = π -x :
lim [ sinx / (π -x) ]
x→π
= lim [ sin(π - y) / y ]
y→0
= lim [ siny / y ]
y→0
= 1


2012-10-16 23:35:38 補充:
Tips :

When x → π ,
y = π -x → π - π = 0.


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