續二次方程(1-10題)

2012-10-16 11:53 am
1.解32x^2 - x^6 =4x^4

2.解17x^2 = 4(1+x^4)

3.解(x-3)^4 -6(x-3)^2+5=0

4.解(x^2 +2x)^2 - 7(x^2+2x)- 8 =0

5.解(x^2 - 4x)^2 -2x(x-4)=15

6.解 x^3 = 9 - 8/x^3

7.解 4/x^4 - 65/x^2 + 16 =0

8.解 1/(x+1)^2 - 1/x+1 - 12 =0

9.解 3/(x^2 -2x)^2 = 1 - 2/x^2-2x

10解 2(x+1) - 5√x+1 +3=0

回答 (1)

2012-10-16 4:29 pm
✔ 最佳答案

1.解32x^2-x^6=4x^4
Sol
x^6+4x^4-32x^2=0
x^2(x^4+4x^2-32)=0
x^2(x^2+8)(x^2-4)=0
x=0(重根) or x=+/-2√2i or x=+/-2

2.解17x^2=4(1+x^4)
Sol
17x^2=4(1+x^4)
4x^4-17x^2+4=0
(4x^4-8x^2+4)-9x^2=0
(2x^2-2)-(3x)^2=0
(2x^2-3x-2)(2x^2+3x-2)=0
(2x+1)(x-2)(2x-1)(x+2)=0
x=-1/2 or x=2 or x=1/2 or x=-2

3.解(x-3)^4-6(x-3)^2+5=0
Sol
y=(x-3)^2
y^2-6y+5=0
(y-1)(y-5)=0
y=1 or y=5
(x-3)^2=1 or (x-3)^2=5
x-3=+/-1 or x-3=+/-√5
x=2 or x=4 orx=3+/-√5

4.解(x^2 +2x)^2-7(x^2+2x)-8 =0
Sol
y=x^2+2x
y^2-7y-8=0
(y-8)(y+1)=0
y=8 or y=-1
x^2+2x=8 or x^2+2x=-1
x^2+2x-8=0 or x^2+2x+1=0
(x-2)(x+4)=0 or (x+1)^2=0
x=2 or x=-4 or x=-1(重根)

5.解(x^2-4x)^2-2x(x-4)=15
Sol
y=x^2-4x
y^2-2y-15=0
(y-5)(y+3)=0
y=5 or y=-3
x^2-4x=5 or x^2-4x=-3
x^2-4x-5=0 or x^2-4x+3=0
(x-5)(x+1)=0 or (x-1)(x-3)=0
x=5 or x=-1 or x=1 or x=3

6.解 x^3 = 9-8/x^3
Sol
x^3 = 9-8/x^3
x^6=9x^3-8
x^6-9x^3+8=0
(x^3-1)(x^3+8)=0
(x-1)(x^2+x+1)(x+2)(x^2-2x+4)=0
x=1 or x=(-1+/-√3i)/2 or x=-2 or x=(1+/-√3i)

7.解 4/x^4-65/x^2+16 =0
Sol
y=1/x^2
4y^2-65y+16=0
(4y-1)(y-16)=0
y=1/4 or y=16
1/x^2=1/4 or 1/x^2=16
x=+/-2 orx=+/-1/4

8.解 1/(x+1)^2-1/(x+1)-12 =0
Sol
y=1/(x+1)
y^2-y-12=0
(y-4)(y+3)=0
y=4 or y=-3
1/(x+1)=4 or 1/(x+1)=-3
x+1=1/4 or x+1=-1/3
x=-3/4 or x=-4/3

9.解 3/(x^2-2x)^2 = 1-2/(x^2-2x)
Sol
y=1/(x^2-2x)
3y^2=1-2y
3y^2+2y-1=0
(3y-1)(y+1)=0
y=1/3 or y=-1
1/(x^2-2x)=1/3 or 1/(x^2-2x)=-1
x^2-2x=3 or x^2-2x=-1
x^2-2x-3=0 or x^2-2x+1=0
(x-3)(x+1)=0 or (x-1)^2=0
x=3 or x=-1 or x=1(重根)

10解 2(x+1)-5√(x+1)+3=0
Sol
y=√(x+1)>=0
2y^2-5y+3=0
(2y-3)(y-1)=0
y=3/2 or y=1
√(x+1)=3/2 or √(x+1)=1
x+1=9/4 or x=1=1
x=5/4 or x=0





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