1.6/(x-2)-3x-1/(x+1)-4=0
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數學問題(Thank you!)
2012-10-16 3:46 am
回答 (3)
2012-10-17 6:09 am
✔ 最佳答案
6/(x-2) - (3x-1)/(x+1) - 4 = 0... 兩邊乘以 (x-2)(x+1) ...
6(x+1) - (3x-1)(x-2) - 4(x-2)(x+1) = 0
6x + 6 - 3x^2 + 7x - 2 - 4x^2 + 4x + 8 = 0
7x^2 - 17x - 12 = 0
(7x + 4)(x - 3) = 0
x = -4/7, 3
2012-10-17 9:15 am
發問者沒有使用括弧,應該 1除(x + 1),是 cubic equation, 沒有這麼簡單
6/(x-2) -3x -1/(x+1) -4 = 0
如果用括弧,(3x – 1), 是 quadratic equation, 比較容易
6/(x-2) -(3x-1)/(x+1) -4 = 0
6/(x-2) -3x -1/(x+1) -4 = 0
如果用括弧,(3x – 1), 是 quadratic equation, 比較容易
6/(x-2) -(3x-1)/(x+1) -4 = 0
2012-10-16 5:57 am
有Ｄ幅雜＝ ＝
1. 6/(x-2)-3x-1/(x+1)-4=0
6/x-2-3x-1/x+1=4
(6x+1)-(6x-1)(x-2)/(x-2)(x+1)=4
6x+1-3x²+6x+-3/(x-2)(x+1)=4
-3x²+13x-2/x²-x-2=4
-3x²+13x-2=4x²-4x-8
-7x²+17x-6=0
希望幫到你=]
1. 6/(x-2)-3x-1/(x+1)-4=0
6/x-2-3x-1/x+1=4
(6x+1)-(6x-1)(x-2)/(x-2)(x+1)=4
6x+1-3x²+6x+-3/(x-2)(x+1)=4
-3x²+13x-2/x²-x-2=4
-3x²+13x-2=4x²-4x-8
-7x²+17x-6=0
希望幫到你=]
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