數學問題(Thank you!)

6/(x-2) - (3x-1)/(x+1) - 4 = 0
... 兩邊乘以 (x-2)(x+1) ...
6(x+1) - (3x-1)(x-2) - 4(x-2)(x+1) = 0
6x + 6 - 3x^2 + 7x - 2 - 4x^2 + 4x + 8 = 0
7x^2 - 17x - 12 = 0
(7x + 4)(x - 3) = 0
x = -4/7, 3

發問者沒有使用括弧,應該 1除(x + 1),是 cubic equation, 沒有這麼簡單
6/(x-2) -3x -1/(x+1) -4 = 0

如果用括弧,(3x – 1), 是 quadratic equation, 比較容易
6/(x-2) -(3x-1)/(x+1) -4 = 0

有Ｄ幅雜＝　＝

1. 6/(x-2)-3x-1/(x+1)-4=0
6/x-2-3x-1/x+1=4
(6x+1)-(6x-1)(x-2)/(x-2)(x+1)=4
6x+1-3x²+6x+-3/(x-2)(x+1)=4
-3x²+13x-2/x²-x-2=4
-3x²+13x-2=4x²-4x-8
-7x²+17x-6=0

希望幫到你=]