1/x^4 - 13/x^2 + 36
請問應該點計???人地話好似係x^-4咁計下去...
一條f.3 maths題 測驗用10分
2012-10-16 3:43 am
回答 (3)
2012-10-16 4:45 am
✔ 最佳答案
To sky_love1997:You haven't factorize it completely.
2012-10-15 20:45:34 補充：
= 1/x⁴ - 13/x² + 36= 1/x⁴(36x⁴ - 13x² + 1)= 1/x⁴(4x² - 1)(9x² - 1)= 1/x⁴(2x – 1)(2x + 1)(3x – 1)(3x + 1)
p.s. sky_love1997’s answer is wrong.
參考: My Maths World
2012-10-17 5:12 am
1/x^4 - 13/x^2 + 36
= (1/x^2 - 4)(1/x^2 - 9)
= (1/x + 2)(1/x - 2)(1/x + 3)(1/x - 3)
= (1/x^2 - 4)(1/x^2 - 9)
= (1/x + 2)(1/x - 2)(1/x + 3)(1/x - 3)
2012-10-16 4:35 am
Thank you for reminding me =)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121015000051KK00479