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Three sleds are being pulled horizontally on frictionless horizontal ice using horizontal ropes (the figure (Figure 1) ). The pull is horizontal and of magnitude 137N .
1. Find the tension in rope A.
?N
2. Find the tension in rope B
?N
Tension
2012-10-13 7:33 am
回答 (1)
2012-10-13 8:51 am
✔ 最佳答案
Total mass of the sleds = (10 + 20 + 30) kg = 60 kgUse: acceleration = force/mass = 137/60 m/s^2 = 2.283 m/s^2
Consider the 10 kg sled, use: force = mass x acceleration
137 - Ta = 10 x 2.283
where Ta is the tension in rope A
Ta = (137 - 22.83) N = 114.17 N
Consider the 30 kg sled,
Tb = 30 x 2.283 N = 68.49 N
where Tb is the tension in rope B
收錄日期: 2021-04-29 17:49:10
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121012000051KK00584