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A load of bricks with mass m1 = 16.0 kg hangs from one end of a rope that
passes over a small, frictionless pulley. A counterweight of mass m2 = 29.0 kg is suspended from the other end of the rope, as shown in the figure. (Figure 1) The
system is released from rest.
What is the magnitude of the upward acceleration of the load of bricks?
? m/s^2
What is the tension in the rope while the load is moving?
?N
Newton's law
2012-10-13 7:08 am
回答 (1)
2012-10-13 8:44 am
✔ 最佳答案
Net force = (29g - 16g) N = 13g N = 130 Nwhere g is the acceleration due to gravity, taken to be 10 m/s^2
Acceleration = net-force/mass = 130/(29+16) m/s^2 = 2.889 m/s^2
Consider the load of bricks, use: force = mass x acceleration
T - 16g = 16 x 2.889
where T is the tension in the rope
T = 206 N
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