complex number
回答 (2)
2012-10-13 3:59 am
✔ 最佳答案
3/(a + bi) = (6 + 2i)/5(a + bi)(6 + 2i) = 15
(6a - 2b) + (2a + 6b)i = 15
We have 6a - 2b = 15, and 2a + 6b = 0
b = -3/4, a = 9/4
2012-10-13 2:58 am
3/a+bi=6+2i/5
3/a+bi = 2(3+i)/5
15/2 = (3+i)(a+bi)
15/2 = 3a+3bi+ai+bi^2
15/2 = (3a-b) + (a+3b)i
By comparing LHS and RHS,
3a -b = 15/2 ------ 1
a+3b = 0 -----------2
∴ a = 9/4 , b = -3/4
3/a+bi = 2(3+i)/5
15/2 = (3+i)(a+bi)
15/2 = 3a+3bi+ai+bi^2
15/2 = (3a-b) + (a+3b)i
By comparing LHS and RHS,
3a -b = 15/2 ------ 1
a+3b = 0 -----------2
∴ a = 9/4 , b = -3/4
收錄日期: 2021-04-22 00:59:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121012000051KK00326