中三續因式分解

2012-10-12 4:20 am
非常趕急,需列詳細步驟!謝謝!!

挑戰題

1a)(2x-3y)(3x+4y)-13xy(十字相乘法)

b)10mn+(m-n)(2m-3n)(十字相乘法)

c)19pq+(3p+4Q)(5Q-2p)(十字相乘法)


萬分感激,謝謝!!

回答 (1)

2012-10-12 5:24 am
✔ 最佳答案
1a)(2x - 3y) (3x + 4y) - 13xy
= 6x² + 8xy - 9xy - 12y² - 13xy
= 6x² - 14xy - 12y²
= 2(3x² - 7xy - 6y²)
3x..... 2y
.....X
x.....- 3y
──────────────
3x(-3y) + x(2y) = - 7xy
= 2 (3x + 2y) (x - 3y)

b)10mn + (m - n) (2m - 3n)
= 10mn + 2m² - 2mn - 3mn + 3n²
= 2m² + 5mn + 3n²
2m......3n
......X
..m......n
─────────────
2m(n) + m(3n) = 5mn
= (2m + 3n) (m + n)
c) 19pq + (3p + 4q) (5q - 2p)
= 19pq + 15pq - 6p² + 20q² - 8pq
= 20q² + 26pq - 6p²
= 2(10q² + 13pq - 3p²)
5q..... - p
......X
2q......3p
───────────────
5q(3p) + 2q(- p) = 13pq
= 2 (5q - p) (2q + 3p)


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