請問有關數學問題???

2012-10-11 6:04 am
1. (2x^3-x^2+9x-10) / (x-1)

2. (16x^3-4x^2-6) / (2x-1)

3. (2x^3-3x^2+4x+3) / (x^2-2x+3)

請詳細 step by step
thanks................

回答 (1)

2012-10-11 10:23 pm
✔ 最佳答案
1. (2x^3-x^2+9x-10)/(x-1)
Sol
2 -1  9 -10|
   2  1  10|1
────────────
2  1 10|  0
(2x^3-x^2+9x-10)/(x-1)=2x^2+x+10

2. (16x^3-4x^2-6)/(2x-1)
Sol
2x-1=0
2x=1
x=1/2
  16 -4 0 -6|
      8 2  1|1/2
─────────────
2|16  4 2|-5
  ───────
   8  2 1
(16x^3-4x^2-6)/(2x-1)=(8x^2+2x+1)…….-5

3. (2x^3-3x^2+4x+3)/(x^2-2x+3)
Sol
2 -3  4  3|2
   4  2   |-3
     -6 -3|
───────────
2  1| 0  0
(2x^3-3x^2+4x+3)/(x^2-2x+3)=2x+1




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