急! F5 Graphs of Functions 3q1

20(a) AP = (8 - x)/2 = 4 - x/2Since AP = QP, we have the area of PQRS isAP * PQ = X(4 - x/2) = 4x - x^2/2(b) AD = 4√2,The height of triangle APD = (8 - X)/√8So, the area of APD is 8 - XThe area of triangle PDS is (4√2)^2/2 - 2(8 - X) = 2x(c) If area of PQRS = area of triangle PDS4x - x^2/2 = 2xx^2/2 - 2x = 0So, from the graph, x = 4(ii) We have 2x = 4x - x^2/2 + 3.5x^2/2 - 2x = 3.5x = 5.32 OR -1.32 (rejected)