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1.(n-10)^2-5n
2.(15-e)(e+2)+18
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中三續因式分解
2012-10-06 9:13 pm
回答 (5)
2012-10-06 9:30 pm
✔ 最佳答案
1)(n - 10)² - 5n= (n² - 20n + 100) - 5n= n² - 25n + 100
n......- 5
....X
n .....- 20
──────────
- 20n - 5n = - 25n
= (n - 5) (n - 20)
2)
(15-e) (e+2) + 18= (15e + 30 - e² - 2e) + 18= - e² + 13e + 48
- e......16
.......X
e .........3
──────────
- 3e + 16e = 13e
= (- e + 16) (e + 3)= (e + 3) (16 - e)
2012-10-07 4:07 pm
1.
(n-10)^2-5n
=n^2-20n+100-5n
=n^2-25n+100
=(n-20)(n-5)
2.
(15-e)(e+2)+18
=15e+30-e^2-2e+18
=-e^2+13e+48
=(e+3)(e-16)
(n-10)^2-5n
=n^2-20n+100-5n
=n^2-25n+100
=(n-20)(n-5)
2.
(15-e)(e+2)+18
=15e+30-e^2-2e+18
=-e^2+13e+48
=(e+3)(e-16)
2012-10-07 4:27 am
1. (n-10)^2-5n
=n^2-20n+10^2-5n
=n^2-25n+100
=(n-5)(n-20)
2. (15-e)(e+2)+18
=15e+30-e^2-2e+18
=13e-e^2+48
=(16-e)(3+e)
=n^2-20n+10^2-5n
=n^2-25n+100
=(n-5)(n-20)
2. (15-e)(e+2)+18
=15e+30-e^2-2e+18
=13e-e^2+48
=(16-e)(3+e)
2012-10-07 2:57 am
(n-10)^2-5n
=(n^2-20n+100)-5n
=n^2-25n+100
=(n-20)(n-5)
(15-e)(e+2)+18
=(-e^2+15e-2e+30)+18
=(-e^2+13e+30)+18
=-e^2+13e+48
=(-e+16)(e+3)
=-(e-16)(e+3)
=(n^2-20n+100)-5n
=n^2-25n+100
=(n-20)(n-5)
(15-e)(e+2)+18
=(-e^2+15e-2e+30)+18
=(-e^2+13e+30)+18
=-e^2+13e+48
=(-e+16)(e+3)
=-(e-16)(e+3)
2012-10-06 9:34 pm
1.(n-10)^2-5n
=(n^2-5n-10^2-5n)
=n^2-5n^2-200-500n
=-4n^2-500n-200
2.(15-e)(e+2)+18
=15e+30-(e^2)-2e+18
=13e+48-e^2
=(n^2-5n-10^2-5n)
=n^2-5n^2-200-500n
=-4n^2-500n-200
2.(15-e)(e+2)+18
=15e+30-(e^2)-2e+18
=13e+48-e^2
收錄日期: 2021-04-21 22:28:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121006000051KK00295