✔ 最佳答案
───────────────── → The edge of the field
|....................................... 5 << Entrance
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W = 70 ...........................60
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|____________________5 >> Exit
............ L = 140 Let L be the length and W be the wide of the temporary parking lot ,then 2W + L - 2(5) = 270
L = 280 - 2W
The area for cars
= W L
= W (280 - 2W)
= - (2W² - 280W)
= - 2(W² - 140W)
= - 2(W² - 2(70)W + 70² - 70²)
= - 2( (W - 70)² - 4900 )
= 9800 - 2(W - 70)²
When W = 70 , the maximum area for cars = 9800 m².
(L = 280 - 2W = 140)