Probability
2012-10-04 11:26 pm
A bag containing 5 red balls and 5 blue balls. Paul and Peter each one draw a ball from the bag without replacement. Find the probability that either or both of them get a red ball.
回答 (3)
2012-10-04 11:48 pm
✔ 最佳答案
P(neither Paul nor Peter get a red ball)= P([Paul gets a blue ball] and [Peter gets a blue ball])
= P(Paul gets a blue ball) x P(Peter gets a blue ball)
= (5/10) x (4/9)
= 2/9
P(either or both of Paul and Peter get a red ball)
= 1 - P(neither Paul nor Peter get a red ball)
= 1 - (2/9)
= 7/9
參考: micatkie
2012-10-05 2:25 am
P(Both of them draw Blue balls)
=5C2/10C2
=2/9
P(either or both of them get a red ball )
=1-2/9
=7/9
=5C2/10C2
=2/9
P(either or both of them get a red ball )
=1-2/9
=7/9
參考: me
2012-10-05 12:06 am
Frist,Paul get a red ball probabilty=50%
Then,Peter get a red ball probabilty=40%
They get a red ball probabilty=40%
Then,Peter get a red ball probabilty=40%
They get a red ball probabilty=40%
收錄日期: 2021-04-13 19:01:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121004000051KK00218