Laws of integral indices
回答 (2)
2012-10-02 5:14 am
✔ 最佳答案
3^(2n-1)/9^(n+1)=3^(2n-1)/3^(2)(n+1)
=3^(2n-1)/3^(2n+2)
=3^(2n-1)-(2n+2)
(3的(2n-1)-(2n+2)次方)
=3^(2n-1-2n-2)
=3^(-3)
=1/3^3
=1/27
參考: myself
2012-09-30 6:49 pm
9^(n + 1) = (3^2)^(n + 1) = 3^[2(n + 1)] = 3^(2n + 2)
Answer = 3^(2n - 1 - 2n - 2) = 3^(- 3) = 1/27.
Answer = 3^(2n - 1 - 2n - 2) = 3^(- 3) = 1/27.
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