The fastest measured pitched baseball left the pitcher's hand at a speed of
44.0m/s . If the pitcher was in contact with the ball over a distance of 1.50m
and produced constant acceleration,
(a) what acceleration did he give the ball,
and (b) how much time did it take him to pitch it?
Physics motion
2012-09-29 3:45 am
回答 (1)
2012-09-29 6:40 am
✔ 最佳答案
(a) Use equation: v^2 = u^2 + 2a.swith v = 44 m/s, u = 0 m/s, s = 1.5 m, a =?
hence, 44^2 = 2.a(1.5)
a = 645 m/s^2
(b) use equation: v = u + at
with v = 44 m/s, u = 0 m/s, a = 645 m/s^2, t =?
hence, 44 = 645t
t = 0.068 s
收錄日期: 2021-04-29 17:46:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120928000051KK00476