高中數學一問題

2012-09-28 2:57 am
高中數學一問題

根28 份之 2

簡化後變成 根7

請問步驟><? 看不懂

回答 (5)

2012-09-28 3:11 am
✔ 最佳答案
根28份之2
=根2x2x7份之2
=2根7份之2 (分母2除分子2=1)
=1根7
=根7

希望幫到你.

2012-09-27 19:12:59 補充:
根2x2x7=>把二個相同數字抽出根出只寫1個,因為2x2=4 , 根4=2
2012-09-30 11:13 pm
2 / +ve Sq. Root ( 28 )
= 2 / [ 2 +ve Sq. Root ( 7 ) ]
= 1 / +ve Sq. Root ( 7 )

Hence all answers were wrong. I am regret for putting Wrong Praise.
2012-09-29 4:53 am
2/√28
=2/√(7×2^2)
=2/√7 ×2
=√7
2012-09-28 11:38 am
{ sqrt[ 28 ] } / 2

= { sqrt[ 2 x 2 x 7 ] } / 2

= { sqrt[ 2 x 2 ] x sqrt[ 7 ] } / 2

= { 2 x sqrt[ 7 ] } / 2

= sqrt[ 7 ]
2012-09-28 3:11 am
高中- -!? 中二黎架wo
仲有應該係 根28 over 2 或 2份之根28 - -5係 根28份之2
√28 / 2 = √(4*7) / 2
=√4 * √7 / 2
=2 * √7 / 2
=√7

2012-09-27 19:12:50 補充:
如果係根28份之2 會出 1/√7 or √7 / 7


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