高中數學一問題

根28份之2
=根2x2x7份之2
=2根7份之2 (分母2除分子2=1)
=1根7
=根7

希望幫到你.

2012-09-27 19:12:59 補充：
根2x2x7=>把二個相同數字抽出根出只寫1個,因為2x2=4 , 根4=2

2 / +ve Sq. Root ( 28 )
= 2 / [ 2 +ve Sq. Root ( 7 ) ]
= 1 / +ve Sq. Root ( 7 )

Hence all answers were wrong. I am regret for putting Wrong Praise.

2/√28
=2/√(7×2^2)
=2/√7 ×2
=√7

{ sqrt[ 28 ] } / 2

= { sqrt[ 2 x 2 x 7 ] } / 2

= { sqrt[ 2 x 2 ] x sqrt[ 7 ] } / 2

= { 2 x sqrt[ 7 ] } / 2

= sqrt[ 7 ]

高中- -!? 中二黎架wo
仲有應該係 根28 over 2 或 2份之根28 - -5係 根28份之2
√28 / 2 = √(4*7) / 2
=√4 * √7 / 2
=2 * √7 / 2
=√7

2012-09-27 19:12:50 補充：
如果係根28份之2 會出 1/√7 or √7 / 7