4x^2-4xy+y^2-2x+y
求祥細答案..謝謝
數學問題 Factorize
2012-09-24 3:11 am
回答 (3)
2012-09-25 4:56 am
002's ans is wrong.
2012-09-24 6:50 pm
4x^2-4xy+y^2-2x+y
=4x^2-4xy-2x+y^2+y
=2x(2x-2y-1)+y(y+1)
=(2x+y)(2x-2y-1)(y+1)
=4x^2-4xy-2x+y^2+y
=2x(2x-2y-1)+y(y+1)
=(2x+y)(2x-2y-1)(y+1)
2012-09-24 4:09 am
4x^2-4xy+y^2-2x+y
=(2x)^2-4xy+y^2-2x+y
=(2x-y)^2-(2x-y)
=(2x-y)(2x-y-1)
=(2x)^2-4xy+y^2-2x+y
=(2x-y)^2-(2x-y)
=(2x-y)(2x-y-1)
收錄日期: 2021-04-13 18:59:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120923000051KK00561