✔ 最佳答案
Let P(n): (x+y)^n - x^n - y^n is divisible by xy(x+y).
When n = 1: (x + y) - x - y = 0 which is divisible by xy(x + y)
Assume that P(k) is true, (x+y)^k - x^k - y^k is divisible by xy(x+y).
When n = k + 1
(x + y)^(k + 1) - x^(k + 1) - y^(k + 1)
= (x + y)^k (x + y) - (x^k) x - (y^k) y
= x[(x + y)^k - x^k - y^k] + y[(x + y)^k - x^k - y^k] + xy^k + yx^k
= x[Axy(x + y)] + y[Bxy(x + y)] + xy[x^(k - 1) + y^(k - 1)]
where A and B are the expressions of variables x and y
As x^(k - 1) + y^(k - 1) is divisible by (x + y), we just prove that
(x + y)^(k + 1) - x^(k + 1) - y^(k + 1) is divisible by (x + y).
So. P(k + 1) is true.
By M.I. for all positive integer n, (x+y)^n - x^n - y^n is divisible by xy(x + y)