用因式分解
2p(3-q)^2-18p
唔識做功課4
2012-09-21 4:14 am
回答 (3)
2012-09-21 4:36 am
✔ 最佳答案
2p(3-q)^2 - 18p=2p[(3-q)^2 - 9]
=2p[(3-q)^2 - 3^2 ]
=2p(3-q+3)(3-q-3)
=2p(6-q)(-q)
=2pq(q-6)//
2012-09-21 4:31 am
其實我用咗a^2-b^2=(a+b)(a-b),所以計到好混亂...
2012-09-21 4:22 am
2p(3-q)^2-18p
=2p(3^2-2q(3)+q^2)-18p
=2p(9-6q+q^2)-18p
=18p-12pq+2pq^2-18p
=2pq^2-12pq
=2pq(q-6)
系5系咁???
E個系咩叫因式分解?
(a-b)^2
=a^2-2ab+b^2
用E條formula ar~
=2p(3^2-2q(3)+q^2)-18p
=2p(9-6q+q^2)-18p
=18p-12pq+2pq^2-18p
=2pq^2-12pq
=2pq(q-6)
系5系咁???
E個系咩叫因式分解?
(a-b)^2
=a^2-2ab+b^2
用E條formula ar~
參考: ME
收錄日期: 2021-04-13 18:58:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120920000051KK00487