✔ 最佳答案
Let x be the number
1. The square root of a positive number is 20 less than the original number.find the number
√x = x – 20
x - √x – 20 = 0
(√x)^2 -√x – 20 = 0
(√x – 5) (√x + 4) = 0
√x = 5
x = 25
√x = - 4. Ignore this
x = 25 (Answer)
2.When 3 is added to a given number,the result is ten times the reciprocal of the number.find the possible value of the number
3 + x = 10(1/x)
3x + x^2 = 10
x^2 + 3x – 10 = 0
(x + 5) (x -2) = 0
x = 2 or x = - 5 (Answer)
3.The sum of a number and its positive square root is 12.find the number
x + √x = 12
(√x)^2 + √x – 12 = 0
(√x + 4)( √x – 3) = 0
√x = -4
x = 16
√x = 3
x = 9
x= 16 or x = 9 (Answer)
4. The sum of a number and its reciprocal is 41/20.find all the possible numbers
x + 1/x = 41/20
x^2 + 1 = 41x/20
20x^2 + 20 = 41x
20x^2– 41x + 20 = 0
Using quadratic formula
x = [-(-41)+- √ (-41)^2 – 4(20)(20))]/2(20)
x = [41+- √ (1681 – 1600)]/40
x = [41+- √ (81)]/40
x = [41+ 9]/40 or x = [41- 9]/40
x = 50/40 = 1.25 or x = 32/40 = 0.8
x = 1.25 or x = 0.8 (Answer)