更新1:
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algebra 1111111111111
2012-09-19 11:31 pm
[IMG]http://i987.photobucket.com/albums/ae355/delaynopemore/4_zpsc7d299aa.jpg[/IMG]
回答 (2)
2012-09-21 4:52 am
✔ 最佳答案
Let P=(x,y,z)The line passing through the point (4,-1,3) which is parallel to (2,-2,5) is(4,-1,3)+t(2,-2,5)=(4+2t,-1-2t,3+5t) where t varies from-∞ to+∞The intersction point then satisfy(4+2t,-1-2t,3+5t)∙(1,-3,-1)=74+2t+3+6t-3-5t=7t=1So the point is (6,-3,8)
2012-09-20 7:29 am
the page is not find
rather you type the question out or post another link
rather you type the question out or post another link
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120919000051KK00241