Find dy/dx for the implicit function.
xy+x=e^y
急問!!!!! M2 FORM4 (20分)
2012-09-08 9:23 pm
回答 (2)
2012-09-08 10:04 pm
✔ 最佳答案
xy' + y + 1 = e^y y'y + 1 = y'(e^y - x)
y' = dy/dx = (y + 1)/(e^y - x)
2012-09-09 5:52 am
xy+x=e^y
d(xy)/dx + 1 = d(exp y)/dx
y + x(dy/dx) + 1 = (exp y)(dy/dx)
(exp y - x)dy/dx = y + 1
dy/dx = (y + 1)/(exp y - x)
d(xy)/dx + 1 = d(exp y)/dx
y + x(dy/dx) + 1 = (exp y)(dy/dx)
(exp y - x)dy/dx = y + 1
dy/dx = (y + 1)/(exp y - x)
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