F.3 maths question

2012-09-08 7:55 am
3b^2(2a-b) - 4a(b-2a)^2 + (b-2a)^3
=?

回答 (1)

2012-09-08 1:02 pm
✔ 最佳答案
I assume it is factorization, not expansion

Factorize:
3b^2(2a-b) - 4a(b-2a)^2 + (b-2a)^3
3b^2 (-1)(b - 2a) - 4a(b-2a)^2 + (b-2a)^3
(-3)b^2(b - 2a) - 4a(b-2a)^2 + (b-2a)^3
(b-2a)^3 - 4a(b-2a)^2 - 3b^2(b - 2a)
(b – 2a){(b-2a)^2 - 4a(b-2a) - 3b^2}
(b – 2a){b^2 -4ab + 4a^2 - 4ab+ 8a^2 - 3b^2}
(b – 2a){12a^2 -8ab - 2b^2}
(b – 2a)2{ 6a^2 -4ab - b^2}
2(b – 2a)(6a^2 -4ab - b^2)

3b^2(2a-b) - 4a(b-2a)^2 + (b-2a)^3 = 2(b – 2a)(6a^2 - 4ab - b^2) (Answer)


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