laws of integral indices
a^n+4 - a^3n
-------------------
a^3n+3 -a^n+7
1
答案係 - -----
a^3
唔識點計...幫幫手,謝謝
一條f.3 maths題
2012-09-07 5:20 am
回答 (4)
2012-09-07 5:32 am
✔ 最佳答案
圖片參考：http://imgcld.yimg.com/8/n/HA00526499/o/701209060059113873365490.jpg
I hopethe solution can help you^^”
參考: I hope the solution can help you^^”
2012-09-11 3:50 am
a^n+4-a^3n
----------------
a^3n+3-a^n+7
a^n+4-a^3n
= -------------------------
a^3 (a^n+3-a^n+4) <-------- a^3 is the common factor of a^3n+3 and -a^n+7
a^n+4-a^3n <--------Can be cancelled (same)
= - --------------------------
a^3 (a^n+4-a^3n) <------- Can be cancelled (same)
1
= - ---------
a^3
My teacher said this is much easier :)
----------------
a^3n+3-a^n+7
a^n+4-a^3n
= -------------------------
a^3 (a^n+3-a^n+4) <-------- a^3 is the common factor of a^3n+3 and -a^n+7
a^n+4-a^3n <--------Can be cancelled (same)
= - --------------------------
a^3 (a^n+4-a^3n) <------- Can be cancelled (same)
1
= - ---------
a^3
My teacher said this is much easier :)
參考: By my own :)
2012-09-07 5:39 am
Notice that the difference between n+4 and n+7 is 3 and the difference between 3n and 3n+3 is 3, too!
[a^(n+4)-a^(3n)]/[a^(3n+3)-a^(n+7)]
= -[a^(3n)-a^(n+4)]
------------------------------
a^3[a^(3n) - a^(n+4)]
= -1/a^3
I hope this can help you a bit. : )
[a^(n+4)-a^(3n)]/[a^(3n+3)-a^(n+7)]
= -[a^(3n)-a^(n+4)]
------------------------------
a^3[a^(3n) - a^(n+4)]
= -1/a^3
I hope this can help you a bit. : )
2012-09-07 5:31 am
Hint:
Try to take out the common factor aⁿ.
Try to take out the common factor aⁿ.
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