✔ 最佳答案
Let B=cost + i sint, C=cos(2t)+ i sin(2t), 0 < t < π, then
∆OAB=(1/2)*1*1 sint
∆OBC=(1/2)*1*1 sint
the ratio is 1
2012-09-07 16:05:32 補充:
Correct:
Let B=k(cost + i sint), C=k²[cos(2t)+ i sin(2t)], 0 < t < π, then
∆OAB=(1/2)*1*k sint
∆OBC=(1/2)*k*k² sint
the ratio is k²=|OB|²
2012-09-07 16:06:12 補充:
k=|OA|=|OB|= 1
2012-09-07 16:38:03 補充:
∠AOB= t
∠BOC= t