1) A hot air balloon is located 400m above the ground.Then it falls slowly at 30m per minute.If +30 represents 30m above the ground,how high is the balloon after 8 minutes?
2) May has 15 plastic balls and 22 sticks.She uses some plastic balls and sticks to make a hexagonal prism,are the remaining materials enough to make a triangulae prism?Explain your answer briefly.
3) Find the distance between each of the following pairs of points which lie on the same vertical line.
(a) A(-2,0),B(-2,-5) (b) C(5,-9),D(5,-11)
4) Find the distance between each of the following pairs of points.
(a) C(-3,-3),D(-3,-7) (b) E(-二分之一 .9),F(二分之五 ,9) (c) G(0,-3),H(0,11)
5) The coordinates of the vertices of a trapezium are A(-2,-1),B(5,-1),C(3,2),D(-1,2) respectively.Find the area of the trapezium.
6) Which of the following points does not lie on the y-axis?
A. (0,-2) B. (0,2) C. (0,0) D. (2,0)
7) Find the distance between the points A(-20,9) and B(11,9).
Distance=
8) Mary has a long string.She first cut 7cm from the string to make a knot,then she cuts the remaining part evenly into three shorter strings.If each smaller part is 28cm long,find the length of the original string by the method of solving equation.
9) A submarine stays at 150m below water surface.It first ascends vertically to a position of 42m below water surface and then descends vertically to a position of 135m below the water surface.If -60m below the water surface,find the total distance travelled by the submarine.
小六升中一嘅英數問題 急!!!!!解答有10點
2012-09-06 1:35 am
回答 (2)
2012-09-06 2:49 am
✔ 最佳答案
1)Height of the ball after 8 minutes
= 400 - 30 x 8 m
= 160 m
= +160
2)
To make a hexagonal prism, we need 12 plastic balls and 18 sticks. Then, 3 plasticballs and 4 sticks are left.
To make a triangular prism, we need 6 plastic balls and 10 sticks. Hence, the remaining materials are NOT enoughto make a triangular prism.
3)
(a)
Distance
= 0 - (-5)
= 0 + 5
= 5 (units)
(b)
Distance
= - 9 - (-11)
= -0 + 11
= 2 (units)
4)
(a)
Distance
= -3 - (-7)
= -3 + 7
= 4 (units)
(b)
Distance
= (5/2) - (1/2)
= 4/2
= 2 (units)
(c)
Distance
= 11 - (-3)
= 11 + 3
= 14 (units)
5)
Area
= [(5 - (-2)) + (3 - (-1))] x [2 -(-1)] ÷ 2
= [(5 + 2) + (3 + 1)] x (2 + 1) ÷ 2
= 16.5 (square units)
6)
The answer is : D. (2, 0)
This is because the x-coordinate of (2, 0) is NOT equal to 0.
7)
Distance
= 11 - (-20)
= 11 + 20
= 31
8)
Let y cm be the length of the original string.
(y - 7) ÷ 3 = 28
y - 7 = 84
y = 91
Hence, the length of the originalstring is 91 cm.
9)
Something has been missed in the question.
參考: 賣女孩的火柴
2012-09-06 1:58 am
May I know what the name of the secondary school is?
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