Linear equation in two unknows
(Steps Please)
1. Solve
5x-6y=1
4/3x-2y=8/3
2.Hence, solve the system of equation
(Let 1/m=x, 1/n=y)
5/m-6/n=1
4/3m-2/n=8/3
Linear equations (2)
2012-09-04 3:19 am
回答 (3)
2012-09-09 2:52 am
1)
5x-6y=1 --------(1)
(4/3)x-2y=8/3 --------(2)
From(2),
(4/3)x-2y=8/3
4x-6y=8 ----------(3)
(1)-(3),
(5x-6y)-(4x-6y)=1-8
5x-4x-6y+6y=-7
x=-7
sub x=-7 into (1),
5(-7)-6y=1
-35-6y=1
-6y=36
y=-6
So,x=-7,y=-6
2)Let x=1/m, y=1/n.
5/m-6/n=1
5x-6y=1
4/3m-2/n=8/3
(4/3)x-2y=8/3
From the solution of Q1,
x=-7, y=-6
So,
1/m=-7
m=-1/7
1/n=-6
n=-1/6
5x-6y=1 --------(1)
(4/3)x-2y=8/3 --------(2)
From(2),
(4/3)x-2y=8/3
4x-6y=8 ----------(3)
(1)-(3),
(5x-6y)-(4x-6y)=1-8
5x-4x-6y+6y=-7
x=-7
sub x=-7 into (1),
5(-7)-6y=1
-35-6y=1
-6y=36
y=-6
So,x=-7,y=-6
2)Let x=1/m, y=1/n.
5/m-6/n=1
5x-6y=1
4/3m-2/n=8/3
(4/3)x-2y=8/3
From the solution of Q1,
x=-7, y=-6
So,
1/m=-7
m=-1/7
1/n=-6
n=-1/6
參考: 自己
2012-09-06 12:37 am
your 2nd eq is
4/3x-2y=8/3
meaning
1. 4/(3x)-2y=8/3 ?
2. 4/(3x-2y)=8/3 ?
3. (4/3)x-2y=8/3 ?
4/3x-2y=8/3
meaning
1. 4/(3x)-2y=8/3 ?
2. 4/(3x-2y)=8/3 ?
3. (4/3)x-2y=8/3 ?
2012-09-04 4:09 am
1.
5x-6y=1---(a)
4x-6y=8---(b)將本來的式子同乘以3
(a)-(b)=>
x=-7
y=-6
2.
(Let 1/m=x, 1/n=y)
5x-6y=1
4/3x-2y=8/3
by 1. x=-7 y=-6
m=-1/7
n=-1/6
5x-6y=1---(a)
4x-6y=8---(b)將本來的式子同乘以3
(a)-(b)=>
x=-7
y=-6
2.
(Let 1/m=x, 1/n=y)
5x-6y=1
4/3x-2y=8/3
by 1. x=-7 y=-6
m=-1/7
n=-1/6
參考: 自己
收錄日期: 2021-04-23 20:44:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120903000051KK00590