請問呢條數應該要點計?
a)Solve x^2-6x=0
b)Using tha results of (a),solve(y^2+5y)^2-6(y^2+5y)=0
中三數學唔識做 求幫手
2012-08-30 8:06 pm
回答 (1)
2012-08-30 9:16 pm
✔ 最佳答案
a)x^2-6x=0
x(x-6)=0
x=0 or x-6=0
x=0 or 6
b)
(y^2+5y)^2-6(y^2+5y)=0
y^2+5y=0 or y^2+5y-6=0
y(y+5)=0 or (y-1)(y+6)=0
y=0 or -5 or 1 or -6
y=-6 or -5 or 0 or 1
參考: me
收錄日期: 2021-04-20 13:14:26
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