come and see see a question!!

2012-08-25 9:10 pm
rewrite 3sin^2x - sinxcosx - 1 = 0 in the from Atan^2x + BtanX + C = 0


where A,B,C are integers!!!!!!!!!!!!
更新1:

http://hk.knowledge.yahoo.com/question/question?qid=7012082400768 ☂雨後陽光☀ help!!!

回答 (1)

2012-08-25 9:16 pm
✔ 最佳答案
3sin²x - sinxcosx - 1 = 03sin²x - sinxcosx - (sin²x + cos²x) = 02sin²x - sinxcosx - cos²x = 0(2sin²x - sinxcosx - cos²x) / cos²x = 0 2 sin²x / cos²x - sinx cosx / cos²x - cos²x / cos²x = 02 tan²x - tanx - 1 = 0

2012-08-25 18:05:27 補充:
喂! 上次在qid=7012040500350你咁攪法,今次唔好喇啩~~


收錄日期: 2021-04-21 22:24:58
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120825000051KK00264

檢視 Wayback Machine 備份