請詳細步驟教我計以下二條 :
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1. May has one cat and dog. Find the probability that they were born in different months.
2. The members of a men's club include Kevin and ten other men. Lily is one of the ten members of a ladies' club. If one person is selected at random from each of the two clubs to join a committee, find the probability that neither Kevin nor Lily are included in the committee.
急! F5 Probability 05c1
2012-08-25 9:19 am
回答 (3)
2012-08-26 2:35 am
✔ 最佳答案
1. P(they were born in the different month)= 12x1/12x11/12
=11/12
2. P(Kevin not in the committee)=10/11
P(Lily not in the committee) =9/10
P(neither Kevin nor Lily are included in the committee)
=10/11x 9/10
=9/11
2012-08-25 7:19 pm
1. P(they were born in the same month)= 12/(12*12) =1/12
P(they were born in different months) =1-1/12 =11/12 //
2. P(Kevin not in the committee)=10/11
P(Lily not in the committee) =9/10
P(neither Kevin nor Lily are included in the committee) =10/11 * 9/10
=9/11 //
P(they were born in different months) =1-1/12 =11/12 //
2. P(Kevin not in the committee)=10/11
P(Lily not in the committee) =9/10
P(neither Kevin nor Lily are included in the committee) =10/11 * 9/10
=9/11 //
2012-08-25 4:41 pm
1.
P(cat was born on a specific month)=1/12
∴The remaining number of months=11
Number of months in a year=12
∴P(they were born in different months)=1/12 x 1/11 x 12=1/11
2.
P(Kevin is not included)=10/(1+10)=10/11
P(Lily is not included)=9/10
∴P(neither of them are included)=10/11 x 1/10=9/11
P(cat was born on a specific month)=1/12
∴The remaining number of months=11
Number of months in a year=12
∴P(they were born in different months)=1/12 x 1/11 x 12=1/11
2.
P(Kevin is not included)=10/(1+10)=10/11
P(Lily is not included)=9/10
∴P(neither of them are included)=10/11 x 1/10=9/11
參考: me
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