F2 數學題

(a²-2a)÷(4a³-8a²)
=a(a-2)÷4a²(a-2)
=1/4a

(a(2次)-2a)/(4a(3次)-8a(2次))
=-2a/(4a(3次)-7a(2次))

2012-08-21 08:06:56 補充：
是-2a/(4a^3-7a^2)才對

(a^2 -2a)/(4a^3-a^2)

= [a(a-2)]/[4a^2(a-2)]

= 1/(4a)