F2 數學題

2012-08-21 4:34 am
(a²-2a)÷(4a³-8a²)

回答 (3)

2012-08-21 4:33 pm
(a²-2a)÷(4a³-8a²)
=a(a-2)÷4a²(a-2)
=1/4a
參考: me
2012-08-21 4:04 pm
(a(2次)-2a)/(4a(3次)-8a(2次))
=-2a/(4a(3次)-7a(2次))

2012-08-21 08:06:56 補充:
是-2a/(4a^3-7a^2)才對
參考: 我
2012-08-21 4:39 am
(a^2 -2a)/(4a^3-a^2)

= [a(a-2)]/[4a^2(a-2)]

= 1/(4a)
參考: 神風亨


收錄日期: 2021-04-20 13:12:20
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