F.5 解方程easy
回答 (2)
2012-08-21 3:06 am
✔ 最佳答案
(3+2/x)(2x-3)=11(6x-9+4-6/x)=(11)
(6x-5-6/x)x=(11)x
6x^2-5x-6=11x
6x^2-16x-6=0
2(3x^2-8x-3)=0
[2(3x+1)(x-3)]=[0]
[2(3x+1)(x-3)]‧1/2=[0]‧1/2
'' (3x+1)(x-3)=0 ''
(3x+1)=0
3x=-1
x=-1/3
(x-3)=0
x=3
x=-1/3 or 3
2012-08-21 3:03 am
( 3+2/x)(2x-3) = 11
(3x+2)(2x-3) = 11x
6x^2 - 16x - 6 = 0
3x^2 - 8x -3 = 0
(3x+1)(x-3) = 0
x = -1/3 or 3
(3x+2)(2x-3) = 11x
6x^2 - 16x - 6 = 0
3x^2 - 8x -3 = 0
(3x+1)(x-3) = 0
x = -1/3 or 3
參考: 神風亨
收錄日期: 2021-04-21 15:29:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120820000051KK00708