sin cos tin please!!!

2012-08-17 11:45 pm
(1-sinx+cosx)(1+sinx-cosx) = 1/2 180<x<270


find x:

回答 (2)

2012-08-18 1:25 am
✔ 最佳答案
(1 - sinx + cosx) (1+ sinx - cosx) = 1/2
1 - (sinx - cosx)² = 1/2
(sinx - cosx)² = 1/2
1 - 2sinx cosx = 1/2
2 sinx cosx = 1/2 ................ (*)
sin(2x) = 1/2
2x = 30° , 150° , 390° , 510° , 750° ....
x = 390°/2 or 510°/2 for 180° < x < 270°
x = 195° or 255°
(sinx + cosx)² = 1 + 2 sinx cosx
(sinx + cosx)² = 1 + 1/2 ........... By (*)
sinx + cosx = ±√(3/2)
For 180° < x < 270° ,
sinx + cosx = - √(3/2) since sinx , cosx < 0.
2012-08-18 1:30 am
(1-sinx+cosx)(1+sinx-cosx)

=1^2 - (sinx - cosx)^2

=1 - (1 - 2sinxcosx)

=2sinxcosx

now, 2sinxcosx = 1/2
i.e. sin2x= 1/2
i.e. 2x=30, 150, .....
x=15, 75, .....


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