ANS: -4/5 <k<4/5
2. Let f(x)=x^2-8x+k and g(x)=k(x+2), where k is a constant. If f(x)>g(x) for any value of x, find the range of values of k
ANS: -16<k<-4
更新1:
我想問點解 1 x^2 - 5kx + 4 > 0 但是Discriminant < 0 ,而不是>0 thank you very much for helping me
更新2:
但係我仲係唔明點解係no real root, If 4+x^2-5kx>0 for any real number x , 佢既意思係唔係話 無論x係咩real number條inequalty 大過0 , 但係點解係no real root 既? 唔該哂你地:)
更新3:
我明白了,THX you very very much!!!!!!!!!!