比例問題 maths!

2012-08-12 1:46 am
a和b有10隻,共有28隻手.............
a有2手,b有4隻手..............

find a:b:

回答 (1)

2012-08-12 3:12 am
✔ 最佳答案
假設有[a有x隻]、[b有y隻]。

(1) ---- x + y = 10
(2) ----2x + 4y = 28

(先試試自己找出x和y)
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From Eq. (1),
(3) ---- x = 10 - y

Substitute Eq. (3) into Eq. (2),
2x + 4y = 28 ==> 2(10 - y) + 4y = 28
==> 20 + 2y = 28
==> 2y = 28 - 20 = 8
==> y = 4

Subsitute y = 4 into Eq. (3),
x = 10 - y ==> x = 10 - 4 = 6

Therefore, x = 6 and y = 4.

Answer:
x:y = 6:4 = 3:2


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