f2 factorization
can u help me to solve this q?
factorize: ax+a+x+1
p^3 + p- p^2 - 1
i don't know how to factorize 1
show your step thx!!!
回答 (3)
✔ 最佳答案
ax+a+x+1
= a(x+1) + 1(x+1)
= (a+1) (x+1)
p^3+p-p^2-1
=2p^3-p^2-1
=2p^1-1
=2p-1
希望可以幫到你=]
ax+a+x+1
= a(x+1) + 1(x+1)
= (a+1) (x+1)
p^3+p-p^2-1
=2p^3-p^2-1
=2p^1-1
=2p-1
ax+a+x+1
=a(x+1)+(x+1)
=(x+1)(a+1)
p^3 + p- p^2 - 1
=p^3-p^2+p-1
=P^2(p-1)+(p-1)
=(p-1)(p^2+1)
2012-08-16 11:05:40 補充:
第二題很明顯是錯誤的, 而且結果也很明顯不是題目要求的因式分解的形式!!
2012-08-16 11:06:37 補充:
我是指"最佳解答" 的第二題
收錄日期: 2021-04-13 18:54:30
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