正負數乘除減ge問題唔識,求解答,急!!!!

2012-08-10 5:05 am
我有d正負數乘除減ge問題唔識,搵人幫我解答+比我步驟,THANKS+感激不盡!
Q1:(+6)x[(+2)-(-3)]
Q2:(-12)x[(-11)-(-14)]
Q3:[(+7)-(+3)]x(-4)
Q4:[(-7)-(-3)]x(-6)
Q5;(+6)x(+2)-(+6)x(-3)
Q6(-12)x(-11)-(-12)x(-14)
Q7:(+7)x(-4)-(+3)x(-4)
Q8:(-7)x(-6)-(-3)x(-6)

回答 (3)

2012-08-10 6:11 pm
✔ 最佳答案
Q1:(+6)x[(+2)-(-3)]
= (+6)x[+2+3] (負負得正)
= (+6)x(+5)
= (+30) (正正得正)

Q2:(-12)x[(-11)-(-14)]
=(-12)x[(-11)+14] (負負得正)
=(-12)x(+3)
=(-36) (正負得負)

Q3:[(+7)-(+3)]x(-4)
=[(+7) -3] (負正得負) x (-4)
=(+4)x(-4)
=(-16) (負負得正)

Q4:[(-7)-(-3)]x(-6)
=[(-7)+3] (負負得正) x (-6)
=(-4)x(-6)
=(+24) (負負得正)

Q5;(+6)x(+2)-(+6)x(-3)
= (+12)(正正得正) - (-18) (正負得負) -->先乘除後加減
= (+12) + 18 (負負得正)
= (+30)

Q6(-12)x(-11)-(-12)x(-14)
=(+132) (負負得正) - (+168) (負負得正) -->先乘除後加減
= (+132) - 168 (負正得負)
= (-36)

Q7:(+7)x(-4)-(+3)x(-4)
= (-28) (正負得負) - (-12) (正負得負) -->先乘除後加減
= (-28) + 12 (負負得正)
= (-16)

Q8:(-7)x(-6)-(-3)x(-6)
= (+42) (負負得正) - (+18) (負負得正)
= (+42) - 18 (負正得負)
= (+24)

2012-08-11 5:03 am
1) (+6)*[(+2)-(-3)]
=(+6)*(+2+3)
=(+6)*(+5)
=+30
2) (-12)*[(-11)-(-14)]
=(-12)*(+14-11)
=(-12)*(+3)
=-36
3) [(+7)-(+3)]x(-4)
=(+7-3)*(-4)
=(+4)*(-4)
=-16
4) [(-7)-(-3)]x(-6)
=(+3-7)*(-6)
=(-4)*(-6)
=+24
5) (+6)x(+2)-(+6)x(-3)
=(+12)-(-18)
=+12+18
=30
6) (-12)x(-11)-(-12)x(-14)
=(+121)-(+168)
=-47
7) (+7)x(-4)-(+3)x(-4)
=(-28)-(-12)
=+12-28
=-16
8) (-7)x(-6)-(-3)x(-6)
=(+42)-(+18)
=+42-18
=24
參考: 我本人
2012-08-10 5:32 am
Q1:(+6)x[(+2)-(-3)]
solve:(+6)X[2+3]=6X5=30

Q2:(-12)x[(-11)-(-14)]
solve:(-12)x[(-11)+14]=(-12)x3=-36

Q3:[(+7)-(+3)]x(-4)
solve:[7-3]x(-4)=4x(-4)=-16

Q4:[(-7)-(-3)]x(-6)
solve:[(-7)+3]x(-6)=(-4)x(-6)=24

Q5;(+6)x(+2)-(+6)x(-3)
solve:6x2-(-18)=30

Q6(-12)x(-11)-(-12)x(-14)
solve:132-168=-36

Q7:(+7)x(-4)-(+3)x(-4)
solve:(-28)-(-12)=(-28)+12=-14

Q8:(-7)x(-6)-(-3)x(-6)
solve:42-18=24


收錄日期: 2021-05-01 23:00:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20120809000051KK01050

檢視 Wayback Machine 備份